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Exam3Sol - Principles of Physics 11 PHYS 2212-161 Exam#3...

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Unformatted text preview: Principles of Physics 11 PHYS 2212-161] Exam #3 Fall 2111!] Name Sol-oi; {m 5- You may use the values k = scam!" N mitcz, a, = 8.85xlfl'uC2fl‘Jn12 , “-0 = 4mglfl'TNfA2, and e = 1.6flxlfl'” c. You must show all ofyour work for full credit. 1. {15 points) A length ofwire carries a current of 3.5!]!11 to the right along the x—axis and extends flow the origin to the point x = 25.0orn . What is the magnetic field Trector at the point (X, y) = (5.133an 5.0mm]? _ g :3. “:Lii ; Chennai Flt-Sinai) . L”? ‘3 Entire» 3940”“ bar“ GI : Still-1th} Q1 qufit. Elites.“ :- f . {fin-FILL ‘ 33% (Strict-{fun ,c 1 ’53 “SEEM 1- Slum-19) ta“ g1 : ficu‘m ,r (91 = 7.2.1:)“ 5mg. : air-7a? SW‘Q‘L: Ct all” 2. {15 points) A parallel-plate capacitor in air has circular plates of radius 3 .5c1n separated by lflnnn . Charge is flowing onto the upper plate and off the lower plate at arate of 15A . 5.} Find the electric field between the plates as a function of tiJne {assume Q = t] at t = fl) . b} Using your electric field from part a) show the displacement current between the plates is “ELSA . GHCV; v“!- Q , a; to}: Answer: | ram 6'2 E: V , £3; , It _ 7a-M4t ~66 .- r .— ,_ _ I 3 3. (it) points) A uniform magnetic field of magnitude 2.35T is in the positive y—direetion. Find theforce on aprotonif'its velocity is a)§= 1.4Mmf'si ,b}§= Lflvtmfsj't, c}fi=3.4lvl_mfsfi , anddjfi=3 ...{ll'udrm'si-d-flmhrlfsf {Iffi istotheright andfrisupthe page, Ewouldbe out of the page.) .61.); WIFE“? “’Lbbafc‘HCO. ‘tufo'l if) (;_3ST§L> 5(537i0f1N1M(1ffi:i> : 2‘. boat-1c" C. (Hf-to ?§)x(fl.3f?§‘) '3 ( C’ f =t.so.1-rc"“£ (3. Li - {s t g1 52> £123.“;ng (in???) ‘2‘— #1“ A A :. “I.l37-rc‘“”1/U 2: ('?:-+13 :- a)? c) e A) "E: J.st31~m"'iid(‘2_d rshmiiftsf-t. oJfi“a_;JE>X(i.iEg’T3“) ..- I'm 7- HZqo’ANc (1%1? at? 1.3;.) 4. [2D points} Anni orrn . magn c e oints out ofthe pageasshownheow Siltlcm x lfiflcm rectangular loop of wire lies on the page corm‘iletel},r within the magnetic field. The loop above starts to move downward on the page at a speed of 1.5flcmfs . Assume that the magnetic field abruptly,r ends along a horizontal line. As the loop leaves the magnetic field... a) What is the change in magnetic flux through it per second? b) What is the direction of the induced magnetic field? c) What is the direction of the induced current in the loop? ‘1) Ifthfl 100p haaareaiatanoe of 6 SIB-fl what is the magnitude of the current? to) if}: (“UFEcQCOmScQMMT '3 G b) 0‘9quth (Lt-Jimmy]; (lit); ’4 8 “A z) 0 @GJGJGJG) . .Li- — ea in [5195. 'fof) amen it's-- so. A) g: —o_i§_r.;f (o_s‘¢rd‘1L/:-..étcrtr tract a. PE; I '- 13: 9.33:1», 5, I:/.0f+ro Musimlq 5. {15 points) An slsctmmagnetic wave with an electfis field ampiimdc nf 'i'lfi‘Wm is incident flflnflflily on a rectangular blank card [that ahsmbs all the radiation) with sides of 492m 11 56cm . Find the force on the card by this radiation. .—-—. fr-i I I ' tins-5.: "us : 7'13 inf/pm f 313th W H gr“: Em -' 513% ._ 1.7l*/G“‘“T ..- _.-—-'—'— __ CL "—‘7' 3.151145%; ,.-- 'H , as S : Emma. 8m; 5W3?“ 217?“? T 4‘73 13%“: Ms Hfh 10‘7U/i4" " PM: 5} : “37%wa __, 3.33154”th " 33%.qung * F: F111;; WA : 51 33. to grifavions CXSZIM ii. (15 points} At {certain instant in time aparticle with charge :1 = 'i'n‘1C is located at x = i}, 3: 3m; its 1.11::11:11:.ii:_1,F at that firm: is v= (15x103n11’s) it + (lfixlfl3n1fs) 3?. Find the magmtic fieldata)fl1enngm, 11)}: 3mg: {1 ,and c)x= fl, y=61n. . a W _ -: 5‘3“ -tt§"?T(—LJ.'7DT’} ~0.':n”?‘§) — .__. 29-bit? 1T2: C) I4+ (0350 M) F: 31M (“5-511 L-LrLith :3 4’69 “9“"; iii": 54L fl‘ ,3 5D IE; +117 10 ‘72:}? ...
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