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# Exam3Sol - Principles of Physics 11 PHYS 2212-161 Exam#3...

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Unformatted text preview: Principles of Physics 11 PHYS 2212-161] Exam #3 Fall 2111!] Name Sol-oi; {m 5- You may use the values k = scam!" N mitcz, a, = 8.85xlﬂ'uC2ﬂ‘Jn12 , “-0 = 4mglﬂ'TNfA2, and e = 1.6ﬂxlﬂ'” c. You must show all ofyour work for full credit. 1. {15 points) A length ofwire carries a current of 3.5!]!11 to the right along the x—axis and extends ﬂow the origin to the point x = 25.0orn . What is the magnetic ﬁeld Trector at the point (X, y) = (5.133an 5.0mm]? _ g :3. “:Lii ; Chennai Flt-Sinai) . L”? ‘3 Entire» 3940”“ bar“ GI : Still-1th} Q1 quﬁt. Elites.“ :- f . {ﬁn-FILL ‘ 33% (Strict-{fun ,c 1 ’53 “SEEM 1- Slum-19) ta“ g1 : ﬁcu‘m ,r (91 = 7.2.1:)“ 5mg. : air-7a? SW‘Q‘L: Ct all” 2. {15 points) A parallel-plate capacitor in air has circular plates of radius 3 .5c1n separated by lﬂnnn . Charge is ﬂowing onto the upper plate and off the lower plate at arate of 15A . 5.} Find the electric ﬁeld between the plates as a function of tiJne {assume Q = t] at t = ﬂ) . b} Using your electric ﬁeld from part a) show the displacement current between the plates is “ELSA . GHCV; v“!- Q , a; to}: Answer: | ram 6'2 E: V , £3; , It _ 7a-M4t ~66 .- r .— ,_ _ I 3 3. (it) points) A uniform magnetic ﬁeld of magnitude 2.35T is in the positive y—direetion. Find theforce on aprotonif'its velocity is a)§= 1.4Mmf'si ,b}§= Lﬂvtmfsj't, c}ﬁ=3.4lvl_mfsﬁ , anddjﬁ=3 ...{ll'udrm'si-d-ﬂmhrlfsf {Ifﬁ istotheright andfrisupthe page, Ewouldbe out of the page.) .61.); WIFE“? “’Lbbafc‘HCO. ‘tufo'l if) (;_3ST§L> 5(537i0f1N1M(1fﬁ:i> : 2‘. boat-1c" C. (Hf-to ?§)x(ﬂ.3f?§‘) '3 ( C’ f =t.so.1-rc"“£ (3. Li - {s t g1 52> £123.“;ng (in???) ‘2‘— #1“ A A :. “I.l37-rc‘“”1/U 2: ('?:-+13 :- a)? c) e A) "E: J.st31~m"'iid(‘2_d rshmiiftsf-t. oJﬁ“a_;JE>X(i.iEg’T3“) ..- I'm 7- HZqo’ANc (1%1? at? 1.3;.) 4. [2D points} Anni orrn . magn c e oints out ofthe pageasshownheow Siltlcm x lﬁﬂcm rectangular loop of wire lies on the page corm‘iletel},r within the magnetic ﬁeld. The loop above starts to move downward on the page at a speed of 1.5ﬂcmfs . Assume that the magnetic ﬁeld abruptly,r ends along a horizontal line. As the loop leaves the magnetic ﬁeld... a) What is the change in magnetic ﬂux through it per second? b) What is the direction of the induced magnetic ﬁeld? c) What is the direction of the induced current in the loop? ‘1) Ifthﬂ 100p haaareaiatanoe of 6 SIB-ﬂ what is the magnitude of the current? to) if}: (“UFEcQCOmScQMMT '3 G b) 0‘9quth (Lt-Jimmy]; (lit); ’4 8 “A z) 0 @GJGJGJG) . .Li- — ea in [5195. 'fof) amen it's-- so. A) g: —o_i§_r.;f (o_s‘¢rd‘1L/:-..étcrtr tract a. PE; I '- 13: 9.33:1», 5, I:/.0f+ro Musimlq 5. {15 points) An slsctmmagnetic wave with an electﬁs ﬁeld ampiimdc nf 'i'lﬁ‘Wm is incident ﬂﬂnﬂﬂily on a rectangular blank card [that ahsmbs all the radiation) with sides of 492m 11 56cm . Find the force on the card by this radiation. .—-—. fr-i I I ' tins-5.: "us : 7'13 inf/pm f 313th W H gr“: Em -' 513% ._ 1.7l*/G“‘“T ..- _.-—-'—'— __ CL "—‘7' 3.151145%; ,.-- 'H , as S : Emma. 8m; 5W3?“ 217?“? T 4‘73 13%“: Ms Hfh 10‘7U/i4" " PM: 5} : “37%wa __, 3.33154”th " 33%.qung * F: F111;; WA : 51 33. to grifavions CXSZIM ii. (15 points} At {certain instant in time aparticle with charge :1 = 'i'n‘1C is located at x = i}, 3: 3m; its 1.11::11:11:.ii:_1,F at that ﬁrm: is v= (15x103n11’s) it + (lﬁxlﬂ3n1fs) 3?. Find the magmtic ﬁeldata)ﬂ1enngm, 11)}: 3mg: {1 ,and c)x= ﬂ, y=61n. . a W _ -: 5‘3“ -tt§"?T(—LJ.'7DT’} ~0.':n”?‘§) — .__. 29-bit? 1T2: C) I4+ (0350 M) F: 31M (“5-511 L-LrLith :3 4’69 “9“"; iii": 54L ﬂ‘ ,3 5D IE; +117 10 ‘72:}? ...
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