# HW21Sol - Jim Guinns PHYS2212 Assignment#21 Solutions 1 a...

This preview shows pages 1–2. Sign up to view the full content.

Jim Guinn’s PHYS2212 Assignment #21 Solutions 1. a.) In a certain material, the speed of light is 2.40x10 8 m/s . What is the index of refraction of this material? We have that n = c / v , so n = (3.00x10 8 m/s) / (2.40x10 8 m/s) = n = 1.25 . b.) In a certain material, the index of refraction is 1.75. What is the speed of light in this material? From the above equation we have v = c / n , so v = (3.00x10 8 m/s) / 1.75 = v = 1.71x10 8 m/s . For indices not given, check your textbook. 2. A block of glass is in air. Light in the air strikes the surface of the glass at an incident angle of 75.0 o . What is the refracted angle in the glass? From Snell's Law we have n 1 sin θ 1 = n 2 sin θ 2 , so letting the air be medium 1 we have sin θ 2 = n 1 sin( θ 1 ) / n 2 = 1.00 sin75.0 o / 1.50 = 0.644 , so θ 2 = sin -1 (0.644) = θ 2 = 40.1 o . 3. A block of glass is submerged in water. Light in the water strikes the surface of the glass at an incident angle of 25.0 o . What is the refracted angle in the glass? From Snell's Law we have n 1 sin( θ 1 ) = n 2 sin θ 2 , so letting the water be medium 1 we have sin θ 2 = n 1 sin( θ 1 ) / n 2 = 1.33 sin25.0 o / 1.50 = 0.375 , so

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern