HW21Sol - Jim Guinns PHYS2212 Assignment#21 Solutions 1 a...

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Jim Guinn’s PHYS2212 Assignment #21 Solutions 1. a.) In a certain material, the speed of light is 2.40x10 8 m/s . What is the index of refraction of this material? We have that n = c / v , so n = (3.00x10 8 m/s) / (2.40x10 8 m/s) = n = 1.25 . b.) In a certain material, the index of refraction is 1.75. What is the speed of light in this material? From the above equation we have v = c / n , so v = (3.00x10 8 m/s) / 1.75 = v = 1.71x10 8 m/s . For indices not given, check your textbook. 2. A block of glass is in air. Light in the air strikes the surface of the glass at an incident angle of 75.0 o . What is the refracted angle in the glass? From Snell's Law we have n 1 sin θ 1 = n 2 sin θ 2 , so letting the air be medium 1 we have sin θ 2 = n 1 sin( θ 1 ) / n 2 = 1.00 sin75.0 o / 1.50 = 0.644 , so θ 2 = sin -1 (0.644) = θ 2 = 40.1 o . 3. A block of glass is submerged in water. Light in the water strikes the surface of the glass at an incident angle of 25.0 o . What is the refracted angle in the glass? From Snell's Law we have n 1 sin( θ 1 ) = n 2 sin θ 2 , so letting the water be medium 1 we have sin θ 2 = n 1 sin( θ 1 ) / n 2 = 1.33 sin25.0 o / 1.50 = 0.375 , so
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