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**Unformatted text preview: **position 7.0 seconds after the engine shutoff is given by: m 9 . 359 ) s . 49 )( s m 8 . 9 ( 2 1 s) . 7 )( s m . 50 ( m 250 2 2 =-+ + = y at which time his velocity is s m 6 . 18 ) s . 7 )( s m 80 . 9 ( s m . 50 2-=-+ = + = gt v v y y Powers thus has s 88 . 6 . 7 88 . 13 =-more time to fall before the helicopter crashes, at his constant downward acceleration of 2 s m 2.0 . His position at crash time is thus: 2 2 1 t a t v y y y y + + = 2 2 ) s 88 . 6 )( s m . 2 ( 2 1 s) 88 . 6 )( s m 6 . 18 ( m 9 . 359-+-+ = m 6 . 184 = or 180 m to the given precision....

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