Homework_3_solution(2)

Homework_3_solution(2) - 1 EE113 Homework 3 Problem 3.2...

This preview shows pages 1–5. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 EE113 Homework 3 Problem 3.2 What is the angular frequency of the sequence x ( n ) = e j 8 n/ 7 ? Solution: By definition, it is 8 7 rad/sec. October 26, 2011 DRAFT 2 Problem 3.4 Order the following sequences according to (a) increasing angular frequencies and (b) decreasing periods: x 1 ( n ) = e- j 3 n , x 2 ( n ) = e- j 6 n , x 3 ( n ) = e- j 5 6 n Solution: By definition, the angular frequencies of x 1 ( n ) , x 2 ( n ) , and x 3 ( n ) are 1 = 5 3 , 2 = 11 6 , 3 = 7 6 and the periods are T 1 = 6 , T 2 = 12 , T 3 = 12 Therefore, (a) The order with increasing angular frequencies: 3 < 1 < 2 (b) The order with decreasing periods: T 2 = T 3 > T 1 October 26, 2011 DRAFT 3 Problem 3.6 What is the period of the sequence x ( n ) = cos ( 6 n- 3 ) ? Solution: The frequency of x ( n ) is = 1 12 . So the period is T = 1 = 12 October 26, 2011 DRAFT 4 Problem 3.8 What is the sequence that results from sampling x ( t ) = cos(50 t ) at the rate of 150 samples per second? What is the angular frequency and period of the sequence? Solution: The sampling rate is 1 150 samples/sec. So the sampling result is x ( n ) = x parenleftBig t = n 150 parenrightBig = cos parenleftBig n 3 parenrightBig The angular frequency is = 3 and the period is T = 6 October 26, 2011 DRAFT 5...
View Full Document

This note was uploaded on 01/24/2012 for the course EE 113 taught by Professor Walker during the Fall '08 term at UCLA.

Page1 / 10

Homework_3_solution(2) - 1 EE113 Homework 3 Problem 3.2...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online