Unformatted text preview: C . W/m 34 . 40 ) 564 . 5 ( m 02 . C W/m. 145 . 2 ° = ° = = i h i Nu D k h C 58 . 79 10 100 30 100 ln 30 10 ln m 02 . m 03 . m 05 . ln ° = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ − − − = ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ − − − = Δ = − = − = i s e s e i i o h T T T T T T T D D D The heat transfer surface area is determined from 2 2 ln ln m 881 . 5 ) C 58 . 79 )( C . W/m 34 . 40 ( W 881 , 18 = ° ° = Δ = ⎯→ ⎯ Δ = T h Q A T hA Q s s & & Then the tube length becomes m 62.4 = = = ⎯→ ⎯ = ) m (0.03 m 5.881 2 2 i s s D A L DL A 877 …. 879 Design and Essay Problems 860...
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This note was uploaded on 01/24/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.
 Fall '10
 Dr.DanielArenas
 Thermodynamics, Convection, Force, Mass, Heat

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