Chapter 11 Fundamentals of Thermal Radiation 11-34A small surface emits radiation. The rate of radiation energy emitted through a band is to be determined. A = 1 cm2T= 1500 K 45°60°AssumptionsSurface Aemits diffusely as a blackbody. AnalysisThe rate of radiation emission from a surface per unit surface area in the direction (θ,φ) is given as φθθθφddIdAQddEeesincos),(==&The total rate of radiation emission through the band between 60°and 45°can be expressed as 444sincos),(44206045TTIddIEbeσππφθθθ====∫∫==since the blackbody radiation intensity is constant (
This is the end of the preview. Sign up
access the rest of the document.