problem02_87 solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.87: Take + y to be downward. Last 1.0 s of fall: 2 2 0 2 2 1 0 0 s) 0 . 1 )( s m (4.9 s) 0 . 1 ( 4 gives + = + = - y y y v h t a t v y y v 0 y is his speed at the start of this time interval. Motion from roof to : 4 3 0 h y y = - ? , 0 0 = = y y v v s m 834 . 3 ) 4 3 )( s m 80 . 9 ( 2 gives ) ( 2 2 0 2 0 2 h h v y y a v v y y y y = = - + = This is v y for the last 1.0 s of fall.
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Unformatted text preview: Using this in the equation for the first 1.0 s gives 9 . 4 834 . 3 4 + = h h m. 270 Then . 5 . 16 : for solve and Let 2 2 = = = = u h u u u h...
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