Thermodynamics HW Solutions 895

Thermodynamics HW Solutions 895 - Chapter 11 Fundamentals...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 11 Fundamentals of Thermal Radiation 11-73 A house located at 40º N latitude has gray-tinted double pane windows. The total solar heat gain of the house at 9:00, 12:00, and 15:00 solar time in July and the total amount of solar heat gain per day for an average day in January are to be determined. Assumptions The calculations are performed for an average day in a given month. Properties The shading coefficient of a gray-tinted double pane window with 6-mm thick glasses is SC = 0.58 (Table 11-5). The incident radiation at different windows at different times are given as (Table 11-4) Solar radiation incident on the surface, W/m 2 Month Time North East South West July 9:00 117 701 190 114 July 12:00 138 149 395 149 July 15:00 117 114 190 701 January Daily total 446 1863 5897 1863 Analysis The solar heat gain coefficient (SHGC) of the windows is determined from Eq.11-57 to be SHGC = 0.87 × SC = 0.87 × 0.58 = 0.5046 The rate of solar heat gain is determined from incident solar, glazing
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/24/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

Ask a homework question - tutors are online