Chapter 11 Fundamentals of Thermal Radiation 11-85A small surface emits radiation. The rate of radiation energy emitted through a band is to be determined. A = 2 cm2T= 600 K 40°50°AssumptionsSurface Aemits diffusely as a blackbody. AnalysisThe rate of radiation emission from a surface per unit surface area in the direction (θ,φ) is given as φθθθφddIdAQddEeesincos),(==&The total rate of radiation emission through the band between 40°and 50°can be expressed as 442050401736.0)1736.0()1736.0(sincos),(TTIddIEbeσπφθθθ====∫∫==since the blackbody radiation intensity is constant (
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