Unformatted text preview: ( [ 48 . ] ) R 1200 ( [( 52 . ){ R Btu/h.ft 10 1714 . ( ) ft 069 . 7 ( 15 . )] ( [ )] ( [ 4 4 3 4 4 3 4 2 8 2 4 2 4 3 32 3 4 1 4 3 31 3 3 − + − ⋅ × = − σ ε + − σ ε = − T T T T F A T T F A Q & Similarly, for the bottom surface of the middle disk, we have ]} ) K 540 ( [ 52 . ] ) R 700 ( [( 48 . ){ R Btu/h.ft 10 1714 . ( ) ft 069 . 7 ( 15 . )] ( [ )] ( [ 4 4 3 4 4 3 4 2 8 2 4 5 4 3 35 3 4 4 4 3 34 3 3 − + − ⋅ × = − σ ε + − σ ε = − − T T T T F A T T F A Q & Combining the equations above, the rate of heat transfer between the disks through the radiation shield (the middle disk) is determined to be and T Btu/h 866 = Q & 3 = 895 K 1243...
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 Fall '10
 Dr.DanielArenas
 Thermodynamics, Mass, Heat, Radiation, Heat Transfer

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