Thermodynamics HW Solutions 954

Thermodynamics HW Solutions 954 - corresponding to this...

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Chapter 12 Radiation Heat Transfer 12-67 A mixture of CO 2 and N 2 gases at 600 K and a total pressure of 1 atm are contained in a cylindrical container. The rate of radiation heat transfer between the gas and the container walls is to be determined. Assumptions All the gases in the mixture are ideal gases. Analysis The mean beam length is, from Table 12-4 8 m 8 m T g = 600 K T s = 450 K L = 0.60 D = 0.60(8 m) = 4.8 m Then, atm ft .36 2 atm m 72 . 0 m) atm)(4.8 15 . 0 ( = = = L P c The emissivity of CO 2 corresponding to this value at the gas temperature of T g = 600 K and 1 atm is, from Fig. 12-36, 24 . 0 atm 1 , = ε c For a source temperature of T s = 450 K, the absorptivity of the gas is again determined using the emissivity charts as follows: atm ft 1.77 atm m 54 . 0 K 600 K 450 m) atm)(4.8 15 . 0 ( = = = g s c T T L P The emissivity of CO 2
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Unformatted text preview: corresponding to this value at a temperature of T s = 450 K and 1atm are, from Fig. 12-36, 14 . atm 1 , = c The absorptivity of CO 2 is determined from 17 . ) 14 . ( K 450 K 600 ) 1 ( 65 . atm 1 , 65 . = = = c s g c c T T C The surface area of the cylindrical surface is 2 2 2 m 6 . 301 4 m) 8 ( 2 m) 8 ( m) 8 ( 4 2 = + = + = D DH A s Then the net rate of radiation heat transfer from the gas mixture to the walls of the furnace becomes W 10 1.91 5 = = = ] ) K 450 ( 17 . ) K 600 ( 14 . )[ K W/m 10 67 . 5 )( m 6 . 301 ( ) ( 4 4 4 2 8 2 4 4 net s g g g s T T A Q & 12-51...
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This note was uploaded on 01/24/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

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