Unformatted text preview: x = 0.4(255ul)/5 = 20.4 ul of 5M stock CaCl 2 255ul20.4ul = 234.6ul water b) dilution in conc = .4M/5M = .08 x final volume 255ul = 20.4ul water is the same as in a) 2) NaAcetate question: a) The set up is the same to start, but you are solving for final volume this time: 50ul (8M) = 0.025M (X) solve for X gives X = 50ul (8M)/0.025M = 16000ul Converting microliters to ml: 16,000 ul (1 ml / 10 3 ul) = 16 ml b) You want to make X ul of 0.025 M stock. Therefore the dilution factor is 0.025 / 8 M = 0.003125. (0.003125) (X) = 50 ul Solving for X gives X=50 ul/ 0.003125 = 16,000 ul 3) NaCl question: 58.4 g/mol, thus a 1 Molar solution: 1M = 58.4g/1L, divide both parts by 2 to get 0.5L = 29.2g/.5L, so 29.2 g is needed to make 500ml of 1M. To get a 0.2 M solution, multiply by .2 , (0.2) 29.2g = 5.84g...
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 Fall '11
 VenkatesanSundaresan
 Mole, 1 mL, 0.4m, 0.5L

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