H2o s 273 k h2o s 263 k because the intial and final

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Unformatted text preview: (s, 273 K) ! H2O (s, 263 K) because the intial and final state are identical for the two pathways. We use the second pathway to calculate !S for the process. H 2 O(l , 263 K) " H 2O(s, 263 K) # $ H 2 O(l , 273 K) " H 2O(s, 273 K) %H = %H sys = nCP ( H 2 O, l ) %T273! 263 + n%H fusion + nCP ( H 2O, s ) %T263! 273 = n%H fusion + n%CP %T = !12.020kJ + 2 ( 75.3 J K -1 ! 36.2 J K -1 ) ( 273.0 K ! 263.0 K ) = !12.020 & 103 J + ( 78.2 J K -1 ) (10.0K ) = !12.020 & 103 J + 7.82 & 102 J = !11.2...
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