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HW2soln-3750

# HW2soln-3750 - EE 3750 HW 2 solutions 1 EE 3750 Homework 2...

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EE 3750 — HW 2 solutions 1 EE 3750 — Homework 2 solutions Spring 2004 1. Given the register and memory contents listed below, list the changed registers and memory locations and their contents after each instruction below executed in sequence. You can identify memory locations by variable name or effective address. Contents: All integers in this problem are written in hexadecimal. Let AX = 9014, BX = 8B77, CX = 00C4, DX = 1744, SP = 266, SI = 362, DI = 440, DS = 5000, ES = 6500, contents of the word at the top of the stack = 3234, contents of the word pointed to by DS:[SI+6] = 8080. ADD AX, BX ADC DX, CX LEA DI, [SI+6] STOSW XCHG CH, CL ADD AX, BX : AX 1B8B ADC DX, CX : DX 1809 LEA DI, [SI+6] : DI 368 : ES:[DI] (= 6500:0368) 1B8B; DI 36A, assuming DF = 0 (but if DF = 1, then DI 366) XCHG CH, CL : CH C4; CL 00

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EE 3750 — HW 2 solutions 2 2. In the following equation, variable Q is a word variable and all other variables are bytes. Q RS T UV + (a) Write an 8086 instruction sequence to compute the equation assuming that the values are given as unsigned binary integers. (b) Write an 8086 instruction sequence to compute the equation assuming that the values are given as signed binary integers. (a) MOV AL, R SUB AL, S ; AL holds R-S MOV AH, 0 ; division by byte-sized divisor T will use dividend AX, so pad value in AL with zeroes DIV T ; AL holds quotient = (R-S)/T; use DIV because unsigned ADD AL, U ; AL holds ((R-S)/T)+U MUL V
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HW2soln-3750 - EE 3750 HW 2 solutions 1 EE 3750 Homework 2...

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