HW1soln-F08

HW1soln-F08 - EE 3750 HW 1 solutions 1 EE 3750 Homework 1...

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EE 3750 — HW 1 solutions 1 EE 3750 — Homework 1 solutions Fall 2008 1. (a) Let the effective address of variable red be 110AH and let DS = 2C10H. What is the corresponding physical address of red , assuming real mode operation? (b) Let the physical address of variable green be 8A930H and let DS = 8600H. What is the corresponding effective address of green , assuming real mode operation? (c) Assume protected mode operation. Let the effective address of variable gray be 1560H and let the base value in the descriptor to which DS points be 54DC34H. What is the corresponding physical address of gray ? All values are given in hex. (a) DS shifted by 4 bits = 2C100 EA = + 110A PA = 2D20A (b) PA = 8A930 DS shifted by 4 bits = 86000 EA = 4930 (c) base address = 54DC34 EA = + 1560 PA = 54F194 2. Explain the sequence of operations performed by the 8086 while executing the instruction MOV [SI+20H], DL . (Be sure to include generation of effective and physical memory address and what happens to both the source and destination operands.)
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This note was uploaded on 01/25/2012 for the course EE 3750 taught by Professor Desouza during the Fall '08 term at LSU.

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HW1soln-F08 - EE 3750 HW 1 solutions 1 EE 3750 Homework 1...

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