Lect2_PresTempDivs2&5ME200SP2012

Lect2_PresTempDivs2&5ME200SP2012 - ME 200...

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ME 200: Thermodynamics I Lecture 2: Temperature, Pressure Problem Solving Procedures
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This Lecture Temperature Pressure Problem Solving Procedure
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Temperature 0 th Law of Thermodynamics: If two bodies are in thermal equilibrium with a third body, then they are in thermal equilibrium with each other Properties of many substances change with temperature in a predictable manner; good for temperature measurement Two Point Scale – Celsius (SI) or Fahrenheit (USCS) » freezing point (0ºC or 32ºF) » boiling point (100ºC or 212ºF)
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Temperature (cont.) Thermodynamic temperature scale based on 2 nd Law Two Point Scale – Kelvin (SI) or Rankine (USCS) » freezing point (273 K) » boiling point (373 K) » T(R) = 1.8 T(K) Temperature differences are identical on different scales in a given system of units » T(ºC) = T(K) » T(ºF) = T(R)
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Temperature (cont.) T(K) = T( C) + 273.15 T(R) = T(°F) + 459.67
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Pressure Force exerted by a fluid per unit area Pascal (SI) or lbf/in
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Lect2_PresTempDivs2&5ME200SP2012 - ME 200...

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