AE202 Final Exam Spring 2009 Solutions

AE202 Final Exam Spring 2009 Solutions - a) 5-9098 +\ c} -...

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Unformatted text preview: a) 5-9098 +\ c} - _L 4H AW 5 A<i (I 4H: M1: 02_ AG“; (2 (2 4H , 3. \0 A0 fa ’ 38,5? a??? : met as lace — 1,40 :345 me, R '4.le MMIS 5) Tflm :‘1 I 9,2943 : mg)? a) am fine“) : r2 = 8.3098 :> we“: HALE: =7 edaefi A) T3 = uqu , Iw m «Law a“ (93946, 3M6 93° ADA“ laces EA“ m7 0“ 5%, EAR (f A w<&¢ an} Co Is JA'QIN. = 49CQOEASJk Ae‘gcw’l‘ura Tax‘u . r l Ms? LE; : _,__<.__\>‘ : = 33%) “q M B' ” "‘“U‘QD = 3919 A0 [+ 9-H Coslggo \l : r- Mm/gefi, I) \6 C I IS\\V‘V\\‘\4rl ‘ - as [[7— lOA) Us 1 [ ESCL‘MK A4 seq \v\ €=1395M5/M3 LL) 3 WES wLeve. vm =: \/\/\To 2 [by V _ [ 9 344.246, 4.3.} "L S _ I _ :2 (0%.? m'3 L935 583 (£35) 6 \] : 440 [A = mo V‘m/kr Q») 3|,ooOl how 0) E L = ifSCva a} «rune, go CL : ‘ w 1 gf S '\J \ I T 4.3:, P = (4444 ML” - 8L 3“on ‘3 C 98? ‘ “Am; T = M + (-.oo<=s°/m) em“ = 92H: QDCML LL34; = L333 A) : 4M ‘45 3 e a“ /M w‘l‘ v = 4‘0‘ ‘03 '“/‘M = 859.8-m/sw U) : QQOIOOO In; " \oalooofiUa = 740,000 Q}: 30 m = 344,880 My . 34%.380. MM ‘ +\Au«\ Ck : _L———_—_—_———2 : g (.44!) 553 (93M) IF CL‘L 4Y9T0L¢k ) \[S ‘ 2 l ‘ 9 CL) mom“ $9. 8 CLNX \ l ‘17. l<*&\‘v\ Y M \/ fi—gV—fiiv— “A v A v fi: ‘rnz‘: Bt‘al' bthL take \5 6 : ’Lam ‘ I A2 \lL Ll)\\efe, E \ 2 < “ e’ > : CD vvvut LlC'oo r\ \ b 6 = Jw I = as; $63 *"‘ ’73—“ ¢ \ MA J, 9P— AK. M> l A\\n_ = 30,000' 4 180’ = 94,950 '. i‘}: : Lane :7 A1 : AL : aqpaso : QCL‘IOALJ‘O M Jame M c 32° ., .. 5 SO.OW\\\lp§ - I Umm ’ 50:} \L—\ = 441 vaw’l/W‘ é) 36,000 (i) D = \)Z .. T " QQBIVSQ H I' TLWJr C» = . :- 399% v -— Q ml ‘ - 99“ W — v. 3 e: 4415-: 41.49 98% ' ‘ MA UM“ z qqgulogwflflr — 9d,? wls C. 4 (293,69) 1. ‘0? S0 9 : l — ¢ 3 (M wk“; ch\ W “mm +L L4 4L4 Lu 7% m lnélx‘v‘b oSe& ow Aflrrcvxcx‘ {wick s w‘LeV‘L \IS 1‘— MX‘S 1 80.?) M‘s“, ) mlqw&\\‘& : ' 9" ,Sfllo ‘ \ I‘nuuaqp 9" CLNK \ = Q 2 = LW 0? I401, l‘.&{“ l ' 3 ' (“Cr ar§\§« 5 m 3 1 2 .440 ‘ \OA) 1 (A) ‘ (“n10 ‘ X = —_— A. / SS %5 1 a ‘ 393,l32\ 0i U C 33< 3 ()3 ~\ P 1:11qu 90 z ——eg—;W\fi\—Etl—WZflTo—L—_,L_ Qa w\v\crz 4‘ {3 (Ltlce\, T: Tkvo.5-\ /\Mdgg ) \JTO (S 0|SSUYMA& VS' ‘1? no w\‘w&' UTO : La = l.2 WIS) : ‘ 95C, ‘33 j"? “at, {s a \«ea&w§w&' wl’l'k S$e¢(& \Iw ); cn‘rflt‘ab vxeaQ MALE) ac\.\\‘e\1e a. firoufl&9f€e& 05: l.Q\JS "\Jm Afar ltd/«4:43 . \ Z ' p. xTo = (79" <\.3\}5 ~ Um) 2-935 wk GU.) Q 2 mlgco ) 2 \ 2 ‘ ‘\ , x : __ law, to?) = ____.____ ms :QSSM T" a; ) a - 4-(993n32) < ‘ W )5 “5'64” * ...
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This note was uploaded on 01/26/2012 for the course AE AE 202 taught by Professor Martin during the Spring '09 term at University of Illinois, Urbana Champaign.

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AE202 Final Exam Spring 2009 Solutions - a) 5-9098 +\ c} -...

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