# HW2sol - ( A B ) = 0.5490 + (1 0.4510) 0.2745 = 0.8235 c) P...

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IE 300 HW2 SOLUTION ASSIGNMENT: 2.18, 20, 34, 38, 40, 50, 74, 83, 101, 150 2-18 memory disk storage 4 8 12 200 300 400 200 300 400 200 300 400 2-20 a) b) c) d) e) 2-34 2 12 = 4096 2-38 From equation 2-1, the answer is 10! = 3,628,800 2-40 From equation 2-3, 7 3 4 35 ! ! ! = sequences are possible

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2-50 a) A B = 56 b) A = 36 + 56 = 92 c) A B = 40 + 12 + 16 + 44 + 56 = 168 d) A B = 40+12+16+44+36=148 e) A B = 36 2-74 a) P(A') = 1- P(A) = 0.7 b) P ( A B ) = P(A) + P(B) - P( A B ) = 0.3+0.2 - 0.1 = 0.4 c) P( ′ ∩ A B ) + P( A B ) = P(B). Therefore, P( ′ ∩ A B ) = 0.2 - 0.1 = 0.1 d) P(A) = P( A B ) + P( A B ). Therefore, P( A B ) = 0.3 - 0.1 = 0.2 e) P(( A B )') = 1 - P( A B ) = 1 - 0.4 = 0.6 f) P( A B ) = P(A') + P(B) - P( ′ ∩ A B ) = 0.7 + 0.2 - 0.1 = 0.8 2-83 P ( A ) = 112/204 = 0.5490, P(B) = 92/204 = 0.4510, P(A B) = (40+16)/204 = 0.2745 a) P ( A B ) = P ( A ) + P ( B ) – P ( A B ) = 0.5490 + 0.4510 – 0.2745 = 0.7255 b) P ( A B ) = (12 + 44)/204 = 0.2745 and P ( A B ) = P ( A ) + P ( B ) – P
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Unformatted text preview: ( A B ) = 0.5490 + (1 0.4510) 0.2745 = 0.8235 c) P ( A B ) = 1 P ( A B ) = 1 0.2745 = 0.7255 2-101 a) 6087 . 92 56 204 / ) 36 16 40 ( 204 / ) 16 40 ( ) ( ) ( ) | ( = = + + + = = B P B A P B A P b) 3913 . 92 36 204 / ) 36 16 40 ( 204 / 36 ) ( ) ' ( ) | ' ( = = + + = = B P B A P B A P c) 5 . 112 56 204 / ) 56 44 12 ( 204 / 56 ) ' ( ) ' ( ) ' | ( = = + + = = B P B A P B A P d) 5 . 112 16 40 204 / ) 44 16 12 40 ( 204 / ) 16 40 ( ) ( ) ( ) | ( = + = + + + + = = A P B A P A B P 2-150 Let A denote the event that a reaction final temperature is 271 K or less. Let B denote the event that the heat absorbed is above target. 6087 . ) 3913 . )( 4510 . ( ) 5 . )( 5490 . ( ) 5 . )( 5490 . ( ) ' | ( ) ' ( ) | ( ) ( ) | ( ) ( ) ( ) ( ) | ( = + = + = = A B P A P A B P A P A B P A P B P B A P B A P...
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## This note was uploaded on 01/26/2012 for the course IE IE 300 taught by Professor Zafarani during the Spring '09 term at University of Illinois, Urbana Champaign.

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HW2sol - ( A B ) = 0.5490 + (1 0.4510) 0.2745 = 0.8235 c) P...

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