ac_circuit - rms rms rms rms I I I Z 2 2 max max rms rms I...

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AC Circuit Given: F i n d : Hz f 65 ? Z 135 rms v ? L 36 ? LR A I rms 5 ? CR F C 64 ? R P ? max R P A series RLC circuit has an AC generator with frequency f = 65 Hz and amplitude E rms = 135 V. The current leads the generator voltage by 36° and the current in the circuit is I rms = 5 A. (a) Calculate the net impedance of the circuit. (b) Calculate the inductance of the circuit, given C = 64 μF. (c) What is the phase of the voltage across the inductor with respect to the voltage across the resistor? A positive value means inductor voltage leads resistor voltage; negative value, vice versa. (d) What is the phase of the voltage across the capacitor with respect to the voltage across the resistor. Positive value means capacitor voltage leads resistor voltage; negative value, vice versa. (e) Calculate the average power dissipated in the resistor. (f) Calculate the peak (instantaneous) power dissipated in the resistor. Solutions a.) To find Z we can use the following formula: 2 max rms 2 max rms  2 max I I rms 2 max rms I I Z I max max
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Unformatted text preview: rms rms rms rms I I I Z 2 2 max max rms rms I Z b.) To find we can use the following formula: L Z X X C L sin sin Z X X C L sin sin rms rms C L I Z X X L X L ; C X L 1 ; f 2 sin rms rms C L I X X sin 2 1 2 rms rms I fC fL f fC I L rms rms 2 2 1 sin NOTE: is negative if the current leads the generator voltage c.) To find LR we can use the following formula: 90 LR d.) To find CR we can use the following formula: 90 CR e.) To find R P we can use the following formula: cos rms rms R I P f.) To find we can use the following formula: max R P cos 2 cos 2 2 cos max max max rms rms rms rms R I I I P cos 2 max rms rms R I P Click here for fast calculation...
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ac_circuit - rms rms rms rms I I I Z 2 2 max max rms rms I...

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