continuous_line_of_charge - Continuous Line of Charge 2.2C...

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Continuous Line of Charge Given: m C / 2 . 2 F i n d : ? x E (0,-3) P ? y E Solutions a.) =0 (because they are inline) x E b.) To find y E we can use the following formula: 2 r dq k E y L q dy dq  2 3 y dy k E y 
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