hw1.5 - c x x q q a k q q q a q k q F E 2 2 60 cos 60 cos a...

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HW1.5 Given: C q a 5 F i n d : ? x F C q b 5 ? y F C q c 4 ? x E cm a 07 . 0 ? y E Solutions a.) To find on we can use the following formula: x F c q .... ˆ 4 2 0 r r QQ F   a b c c b c a c b c a x q q a q k a q kq a q kq r a q kq r a q kq F 2 2 2 2 2 60 cos 60 cos 60 cos ˆ ˆ a b c x q q a q k F 2 60 cos f o r m e F =0 x
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b.) To find on we can use the following formula: y F c q .... ˆ 4 2 0 r r QQ F   a b c c b c a c b c a y q q a kq a q kq a q kq r a q kq r a q kq F 2 2 2 2 2 60 sin 60 sin 60 sin ˆ ˆ  a b c y q q a kq F 2 60 sin c.) To find x E on we can use the following formula: c q   a b c a b c
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Unformatted text preview: c x x q q a k q q q a q k q F E 2 2 60 cos 60 cos a b x q q a k E 2 60 cos d.) To find y E on we can use the following formula: c q a b c a b c c y y q q a k q q q a kq q F E 2 2 60 sin 60 sin a b y q q a k E 2 60 sin...
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This note was uploaded on 01/26/2012 for the course PHYSICS 211 taught by Professor Selig during the Fall '10 term at University of Illinois, Urbana Champaign.

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hw1.5 - c x x q q a k q q q a q k q F E 2 2 60 cos 60 cos a...

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