hw6.6 - 1 1 1 2 1 3 1 R R R R A 3 2 1 I I I B V V C b.) To...

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HW 6.6 Given: V F i n d : 11 V ? 0 . 1 I 4000 1 R ? 0 . 2 I ? 0 . 3 2500 2 R I 2300 3 R ? . 1 I ? . 2 I F C C 2 2 1 ? . 3 I ? . 1 Q ? . 2 Q A circuit in the diagram consists of an ideal battery ( E = 11 V), three resistors ( R 1 = 4000 , R 2 = 2500 , and R 3 = 2300 ), and two capacitors ( C 1 = C 2 = 2 μF). Both capacitors are uncharged at t = 0 when the switch is closed. (a) Calculate the currents in the circuit immediately after the switch is closed. (b) Calculate the currents in the circuit a long time after the switch is closed. (c) Calculate the final charges on the capacitors. Solutions a.) To find , & we can use the following formula: 0 . 1 I 0 . 2 I 0 . 3 I We need two loop equations and one current equation 3 2 1 I I I 0 0 3 3 1 1 I R I R V since 0 2 1 2 2 1 1 c c V V I R I R V q 0 2 1 c c V V
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After algebra… you get 3 2 1 2 1 1 3 R R R R R V R V I 2 1 R R 1 3 2 1 2 1 2 1 1 3 1 R R R R R R R R V R V R V I 3 1 2 I I I Best way to solve the question is to use a Matrix
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Unformatted text preview: 1 1 1 2 1 3 1 R R R R A 3 2 1 I I I B V V C b.) To find I , & we can use the following formula: . 1 . 2 I . 3 I since capacitors are charged 2 I 3 1 3 1 I I R R V I 3 1 3 1 R R V I I c.) To find x we can use the following formula: 1 since same capacitance and same charge(series) 2 1 3 c c V V V 2 1 c c V V 3 1 3 3 3 3 R R V R I R V 3 1 3 1 3 2 2 R R V R C V C CV Q 3 1 3 1 . 2 . 1 2 R R R VC Q Q Click here for fast calculation...
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This note was uploaded on 01/26/2012 for the course PHYSICS 211 taught by Professor Selig during the Fall '10 term at University of Illinois, Urbana Champaign.

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hw6.6 - 1 1 1 2 1 3 1 R R R R A 3 2 1 I I I B V V C b.) To...

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