hw6.11 - point where the particle exits the magnetic field...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
HW 6.11 Given: Find: s m v / 10 5 . 2 6 0 ? 0 v m d 2 . 1 1 ? R / T B 01 . 0 ? m q 11 ? 2 d A charged particle with initial velocity v 0 = 2.5 × 10 6 m/s in the positive x -direction enters a region of depth d 1 = 1.2 m that has a uniform magnetic field B = 0.01 T in the positive z -direction (out the page). The magnetic field is zero elsewhere. The particle leaves the magnetic field region with a velocity vector at an angle = 11 of x -axis. o with respect to the (a) What is the magnitude v 0 ' of the particle's velocity when it exits the magnetic field region? (b) What is the radius of curvature R of the particle's trajectory when in the region of the magnetic field? (c) Calculate the ratio q / m of the charge to the mass of the particle. Be sure to include the correct algebraic sign in your answer. (d) Calculate the displacement d 2 in the y -direction of the particle from its original trajectory at the
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon