# hw6.11 - point where the particle exits the magnetic field...

This preview shows pages 1–2. Sign up to view the full content.

HW 6.11 Given: Find: s m v / 10 5 . 2 6 0 ? 0 v m d 2 . 1 1 ? R / T B 01 . 0 ? m q 11 ? 2 d A charged particle with initial velocity v 0 = 2.5 × 10 6 m/s in the positive x -direction enters a region of depth d 1 = 1.2 m that has a uniform magnetic field B = 0.01 T in the positive z -direction (out the page). The magnetic field is zero elsewhere. The particle leaves the magnetic field region with a velocity vector at an angle = 11 of x -axis. o with respect to the (a) What is the magnitude v 0 ' of the particle's velocity when it exits the magnetic field region? (b) What is the radius of curvature R of the particle's trajectory when in the region of the magnetic field? (c) Calculate the ratio q / m of the charge to the mass of the particle. Be sure to include the correct algebraic sign in your answer. (d) Calculate the displacement d 2 in the y -direction of the particle from its original trajectory at the

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document