HW 10.6
Given:
Find:
A
26
max
m
I
?
max
L
V
H
50
m
L
?
max
C
V
?
max
V
59
max
C
V
C
U
Hz
f
.
5500
?
max
f
?
C
The peak current in an LC circuit is
I
max
= 26 mA. The inductance is fixed at
L
= 50 mH.
The
capacitance is variable and has a rating (breakdown voltage) of
V
C
max
= 59 V.
(a) If the circuit is oscillating at a frequency
f
= 5500 Hz, what is the peak voltage across
L
?
(b) For the same conditions, calculate the peak voltage across
C
.
(c) Calculate the peak energy stored in the capacitor under the above conditions.
(d) What is the highest frequency at which this circuit can operate safely for the given peak
current?
(e) Calculate the capacitance that produces the resonant frequency calculated in part (d).
Solutions
a.)
To find
max
we can use the following formula:
L
V
fL
L
X
L
2
fL
I
X
I
V
L
L
2
max
max
max
fL
I
V
L
2
max
max
b.)
To find
we can use the following formula:
max
C
V
fL
I
V
V
L
C
2
max
max
max
since
0
loop
V
fL
I
V
C
2
max
max

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