light_passing_through_triangular_medium

light_passing_through_triangular_medium - 45 sin sin 45 sin...

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Light Passing Through Triangular Medium Given: F i n d : 2 . 1 2 n ? out 75 in A transparent object with an isosceles right triangular cross-section has an index of refraction n 2 = 1.2, as shown in the diagram below. A light beam in air is incident on this object, making an angle in = 75° with respect to the x-axis, as shown. At what angle (with respect to the x-axis), out , does the observer see the light beam exit the object? Solutions a.) To find out we can use the following formula:

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2 2 ) sin( ) sin( n in 2 1 2 ) sin( sin n in 2 1 2 4 ) sin( sin 90 90 180 n in  45 ) sin( sin ) sin( sin 90 45 45 90 180 2 1 2 1 4 5 n n in in ) sin( ) sin( 6 2 5 n 
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Unformatted text preview: 45 ) sin( sin 45 ) sin( sin sin sin ) sin( sin 2 1 2 2 2 1 1 2 5 1 6 n n n n n in in 45 45 ) sin( sin 45 2 1 2 6 n n in out 45 45 ) sin( sin 2 1 2 n n in out Click here for fast calculation...
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light_passing_through_triangular_medium - 45 sin sin 45 sin...

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