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potential_energy_for_system_of_point_charges

# potential_energy_for_system_of_point_charges - Q Q d Q U U...

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Potential Energy for System of Point Charges Given: C Q 4 . 4 1 Find: ? U C Q 4 . 4 2 C Q 7 . 2 3 C Q 2 . 2 4 C Q 7 . 0 5 cm d 1 Solutions a.) To find if is moved from the point (2,2) to the point (2,-2) we can use the following formula: U 2 Q ...) 4 ( ...) 4 ( 1 0 2 0 1 2 p p r QQ r QQ U U U   2 2 0 4 5 0 3 5 2 2 0 2 5 0 1 5 1 4 2 4 2 4 4 4 4 4 4 d d Q Q d Q Q d d Q Q d Q Q U     5 2 2 2 8 4 3 2 1 0 5 1 Q Q Q Q d Q U 

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d Q Q d d Q Q d Q Q d d Q Q U 2 4 4 2 4 4 4 4 4 4 0 4 5 2 2 0 3 5 0 2 5 2 2 0 1 5 2     4 3 2 1 0 5 2 5 2 2 2 8 Q Q Q Q d Q U 
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Unformatted text preview: Q Q d Q U U U 5 2 2 2 5 2 2 2 8 4 3 2 1 4 3 2 1 5 Q Q Q Q Q Q Q Q d Q U 5 2 2 2 5 2 2 2 8 4 3 2 1 4 3 2 1 5 Q Q Q Q Q Q Q Q d Q U...
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