square_current_loop - cos 2 B Nid B A Ni B cos 2 B Nid...

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Square Current Loop Given: F i n d : T B 8 . 1 ? M cm d 20 12 N A i 85 . 0 30 A uniform magnetic field B = 1.8 T points in the + x direction. A square loop with sides of length d = 20 cm, N =12 turns, and current I = 0.85 A/turn pivots without friction around a pin about the z -axis as shown in the figure below.(The z -axis points out of the page in the left hand panel.) A mass M is hung from one side of the loop (C or D), and the loop is in equilibrium when it makes an angle of 30° with respect to the x-z plane. Determine the size of the mass. Enter a positive number if it is hung from C and a negative number if it is hung from D. Solutions a.) To find M we can use the following formula: 1. write the formula for torque created by the B-Field
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Unformatted text preview: cos 2 B Nid B A Ni B cos 2 B Nid Note: you would think the formula should be sin 2 B Nid but in this case its cos because of the angle they gave us its not the angle between and B instead its between the loop and the x-z plane 2. now we need a torque equation created by the mass (phys 211) cos 2 2 mg d mg d mg r F r cos 2 mg d 3. The torques must be equal so that the system is in equilibrium cos cos 2 2 B Nid mg d NidB mg 2 g NidB M 2...
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This note was uploaded on 01/26/2012 for the course PHYSICS 211 taught by Professor Selig during the Fall '10 term at University of Illinois, Urbana Champaign.

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square_current_loop - cos 2 B Nid B A Ni B cos 2 B Nid...

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