two_capacitors_and_a_battery - Q Q Q 1 Q 2 Q 2 1 2 1 C C C...

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Two Capacitors and a Battery Given: F C 25 1 Find: ? 2 Q F C 80 2 ? 1 Q v 17 V ? 2 Q ? U Two capacitors ( C 1 = 25 μF and C 2 = 80 μF) and a battery ( V = 17 V) are connected in a circuit with a switch S as shown. C 1 is initially uncharged. The switch is set to connect C 2 to the battery. What is the charge Q 2 on C 2 ? The switch is now thrown to the left disconnecting C 2 from the battery and connecting the two capacitors. Calculate the resulting charges Q 1 ' and Q 2 ' on the positive plates of C 1 and C 2 , respectively, when equilibrium is achieved. Calculate the energy lost to the circuit after the switch is thrown to the left and the charges have come to rest. Solutions a.) To find we can use the following formula: 2 Q V Q C CV Q V C Q 2 2
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b.) To find & we can use the following formula: 1 Q 2 Q Where & are the charges on the capacitors before the second capacitor is connected 2 2 1 2 1 Q Q
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Unformatted text preview: Q Q Q 1 Q 2 Q 2 1 2 1 C C C V Q C C Q V 2 1 2 2 1 2 1 C C V C C Q V 2 1 2 1 1 1 1 C C V C C V C Q 2 1 2 1 1 C C V C C Q 1 2 2 Q Q Q c.) To find U we can use the following formula: 1 2 U U U 2 2 2 2 1 2 2 2 2 1 2 1 2 2 2 1 2 2 1 1 5 . 2 1 2 1 2 1 V C C C V C C C C V C C V C V C V C U 2 2 2 2 1 2 2 2 2 1 2 1 5 . V C C C V C C C C V C C U Click here for a fast calculation...
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two_capacitors_and_a_battery - Q Q Q 1 Q 2 Q 2 1 2 1 C C C...

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