two_loop_rl_circuit - Two Loop RL Circuit Given: 102 v...

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Given: 102 v F i n d : ? 2 I H L 8 . 2 ? L V 14 1 R  ? 0 3 dt dI 25 2 R ? 2 I 25 3 R   ? 2 T I 0 t The elements in the circuit shown above have the following values: E = 102 V, L = 2.8 H, R 1 = 14 , R 2 = 25 , and R 3 = 29 . After the switch has been open for a long time, it is closed at t = 0. (a) Calculate the current through R 2 at t = 0+. (b) Calculate the potential drop across the inductor at t = 0+. (c) At what rate is the current through the inductor increasing at t = 0+? (d) After a long time, what is the current through R 2 ? (e) After being closed for a long time, the switch is opened at time T . What is the current through R 2 immediately afterward? (Note: A positive value denotes current traveling in the direction shown in the diagram.) Solutions a.) To find we can use the following formula: 2 I Since 0 3 I We get the following equation 0 2 2 1 1 R R I
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This note was uploaded on 01/26/2012 for the course PHYSICS 211 taught by Professor Selig during the Fall '10 term at University of Illinois, Urbana Champaign.

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two_loop_rl_circuit - Two Loop RL Circuit Given: 102 v...

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