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Unformatted text preview: 2 = 0 to 90°. Calculate the intensity of the light after it has passed through the second polarizer for the following values of 2 . Express each answer as a fraction of I , the original intensity of the light before the first polarizer. Solutions a.) To find 1 I I we can use the following formula: 2 1 I I 2 1 2 1 1 I I I I I I 2 1 1 I I b.) To find 1 E E we can use the following formula: 1 E E 1 1 1 E E E E E E 1 1 E E c.) To find we can use the following formula: on Polarizati axisy along LP on Polarizati 1 d.) To find 2 I I we can use the following formula: 2 1 I I 2 1 2 2 1 2 1 2 cos 2 cos I I I 2 cos cos 2 2 1 2 2 1 2 2 2 I I I I I I 2 cos 2 1 2 2 I I Click here for fast calculation...
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This note was uploaded on 01/26/2012 for the course PHYSICS 211 taught by Professor Selig during the Fall '10 term at University of Illinois, Urbana Champaign.
 Fall '10
 Selig
 Light, Polarization

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