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# two_polarizers - 2 = 0 to 90° Calculate the intensity of...

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Two Polarizers Given: Find: 90 1 ? 0 1 I I x 2 ? 0 1 E E ? on Polarizati ? 0 2 I I A right circularly polarized beam of light of intensity I 0 is propagating in the + z direction. Two linear polarizing sheets are lined up perpendicular to the beam. The first sheet has its transmission axis at an angle 1 = 90° with respect to the x -axis. The transmission axis of the second is variable. (See lower panels of the figure.) (a) Calculate the intensity I 1 of the light after it has passed through the first polarizer. Express your answer as a fraction of I 0 . (b) Calculate the peak electric field amplitude E 1 of the light after it has passed through the first polarizer. Express your answer as a fraction of the peak electric field amplitude E 0 of the initial beam. (c) Describe the state of polarization of the light after it has passed through the first polarizer. With CP = circular polarized and LP = linear polarized, answer: 1 if unpolarized, 2 if CP, 3 if LP along y -axis, 4 if LP along x -axis, or 5 if LP at 45° to the x -axis (d) The second polarizer is rotated through the range

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Unformatted text preview: 2 = 0 to 90°. Calculate the intensity of the light after it has passed through the second polarizer for the following values of 2 . Express each answer as a fraction of I , the original intensity of the light before the first polarizer. Solutions a.) To find 1 I I we can use the following formula: 2 1 I I 2 1 2 1 1 I I I I I I 2 1 1 I I b.) To find 1 E E we can use the following formula: 1 E E 1 1 1 E E E E E E 1 1 E E c.) To find we can use the following formula: on Polarizati axis-y along LP on Polarizati 1 d.) To find 2 I I we can use the following formula: 2 1 I I 2 1 2 2 1 2 1 2 cos 2 cos I I I 2 cos cos 2 2 1 2 2 1 2 2 2 I I I I I I 2 cos 2 1 2 2 I I Click here for fast calculation...
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