# l10anno - Friction Coulombs law P 1 constitutive relation 2...

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Friction: Coulomb s law Two possibilities Stick: Slip x 0 | F f |   | N | P x y Negative friction power (+ve Maximum friction force F f x 0 | F f |   | N | F f , x as drawn) x W N P f F 1. constitutive relation 2. motion (velocity) force F f x 0 | F f |   | N |
Friction Two possibilities Stick: Slip f F B x B A B A f F x A x B | F f |   AB | N AB | AB N AB N  x A B W A W A P B P A P AB x y B P Negative friction power (+ve Maximum friction force F f ( x A x B ) 0 | F f |   AB | N AB | F f , x A and x B as drawn) x A x B

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Friction: Alternatively With constant accelerations and equal initial velocities so that Stick: Slip: x A ( t ) x B ( t ) | F f |   | N AB | F f ( x A x B ) 0 | F f |   | N AB |  x A x B | F f |   | N AB | F f ( x A x B ) 0 | F f |   | N AB | x A ( t ) x B ( t ) ( x A x B ) t with t 0 x A (0) x B (0)
Friction: Check With constant accelerations and equal initial velocities ·( ) 0 || fA B f F Fvv N B A B A AB f F A v B v N f F N ) 0 B f F Faa N

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0.3  k 0g 1 A m k 2 B m P 0 Find and for 80 N and 90 N PP  x A x B
f F f F AB N AB N B W B N A W P m A  x A Assume sticking x A x B x A x B ,f o r P 80 N F f ( x A x B ) 0 | F f |   | N AB | 29.3 m B x B x A x B F f m A x A W A N AB 0 F f P m B x B W B N AB N B 0 x A 2.67 m/s x B 2.67 m/s N B 294.3 N N

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l10anno - Friction Coulombs law P 1 constitutive relation 2...

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