DQ6C_solution - Discussion Question 6C P212, Week 6 Mixing...

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Discussion Question 6C P212, Week 6 Mixing Methods in Resistor Network Analysis In the previous question, you analyzed a “2-loop” circuit. In such cases, the linear algebra is relatively easy. But circuits of 3 loops or more are another story, the linear algebra can become really time consuming! Consider the circuit below. Your tasks are: (a) Find the current I 4 through resistor R 4 . (b) Find the potential difference V B – V A . This circuit looks like a truly horrible 3-loop affair … but it isn’t! With two batteries arranged as shown, we will need to use method 2 = Kirchoff’s Laws. But we can greatly simplify our lives by first applying method 1 = the “collapse” of series and parallel resistor combinations as much as possible. Go for it! Solve for the quantities requested in (a) and (b) using a combination of methods 1 and 2. 20 5 10 0 6 += = In fact this circuit and is very simple. There are two unknown currents and they are easy to solve for. Lower loop from neg term of 20 V battery (clockwise) -
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This note was uploaded on 01/26/2012 for the course TAM 210 taught by Professor Staff during the Fall '08 term at University of Illinois, Urbana Champaign.

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DQ6C_solution - Discussion Question 6C P212, Week 6 Mixing...

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