Unformatted text preview: Z = - .0533/.0004125 sqaureroot Z = - 2.63 Z table shows that the probability will be .0043 P = .0043 Based on the probability it seems that the candidate would have an unlikely chance of retaining 55% of votes from the county. (3) 1 bedroom = $500 per month Of a random sample = 50 one bedroom apartments Sample mean = $530 Standard Deviation $100 Z = $530 - $550/100/50 sqaureroot Z = - 20/14.1421 Z = - 1.41 According to z table the probability for a random sample of 50 one bedroom apartments would be .0786 P =.0786...
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- Spring '11
- Standard Deviation, Candidate, Sample Distribution