CHEM 1&2 Lab Manual & worksheets pg 106

CHEM 1&2 Lab Manual & worksheets pg 106 -...

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Experiment 9: VSEPR General Chemistry I and II Lab Manual Dakota State University Page 106 of 232 5 0 Trigonal Bipyramidal Trigonal Bipyramidal^ 5 1 Trigonal Bipyramidal See-Saw 5 2 Trigonal Bipyramidal T-Shaped 5 3 Trigonal Bipyramidal Linear* 5 4 Trigonal Bipyramidal Linear 6 0 Octahedral Octahedral+ 6 1 Octahedral Square Pyramidal 6 2 Octahedral Square Planar+ 6 3 Octahedral T-Shaped 6 4 Octahedral Linear* 6 5 Octahedral Linear * These shapes are highly symmetrical if all atoms bonded to the central element are identical. + These shapes are highly symmetrical if diametrically opposed elements are identical. ^ Trigonal Bipyramidal is a highly symmetrical shape if both elements on the axis are identical and all three elements in the plane are identical. VSEPR: Some Examples and Shapes Let's take a look at some of these shapes. Doing this will also prove to be useful in showing how to use VESPR. The three-dimensional figures below were generated using
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Unformatted text preview: Chem3D. Here at Dakota State University, we use HyperChem, which will be the last portion of this exercise. Example 1: COH 2 First, we determine the Lewis-Dot structure. Hopefully, by now you are relatively skilled at this. The Lewis-Dot structure would look as follows: Now we determine the central element, which in this case is fairly obviously carbon. To determine the set number, we notice that carbon has no lone pair electrons (we ignore the lone pairs on the oxygen because they are not associated with the central element). We further notice that there are three atoms attached directly to carbon (even though there is a double bond to oxygen, it is only one element). Therefore, the set number is 3. Looking at our table, we see that the parent structure for this molecule is trigonal planar. Looking further, with no lone pair electrons, the molecular shape is also trigonal planar. Here is how it looks from a couple of different viewpoints:...
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