Unformatted text preview: αol3one is 318.50 g/mol, then how many moles (abbreviated mol) would you have if you had 15.00 g? Answer: Just what is this stuff? Dunno. ..don't care, at least not for this problem. Factor label tells us the answer is 0.04710 mol. Problem 4: OK, now let's combine the two types of problems, and see how we do. If we need 0.5000 moles of 3hexyne, which has a molecular weight of 82.15 g/mol and density of 0.7231 g/mL, what volume in mL do we need to get? Answer : Two step problem here, and one of the types of problems that tends to give students much grief. The answer is 56.80 mL. ..how'd you do?...
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 Fall '11
 JosephWalter
 Chemistry, Molecule, factor label method, 1.085 g

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