MGT2251_Quiz2_090111

# MGT2251_Quiz2_090111 - 1 12 X 2 Subject to C1 4 X 1 8 X 2...

This preview shows page 1. Sign up to view the full content.

MGT2251_Quiz2_090111 X 2 C4 : X1 >= 0 MAX 24X1 + 12X2 12 ObjCoeff= 24 12 FEASIBLE EXTREME POINTS OBJECTIVE 11 Point X1 X2 VALUE 1 0 2 24 2 5 2 144 10 3 5 3.5 162 MAX. 4 0 6 72 9 C2 : X1 <= 5 OBJ Function 4 = 72 GRAPH worth 5 points 8 OBJ Function 3 = 162 "each incorrect constraint" = -1 7 " incorrect feasible region" = -1 6 C1 : 4X1 + 8X2 <= 48 5 4 LP C3 : X2 >= 2 3 FEASIBLE C3 : X2 >= 2 REGION 2 C5 : X2 >= 0 1 C5 : X2 >= 0 X 1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 OBJ Function 1 = 24 OBJ Function 2 = 144 C4 : X1 >= 0 C2 : X1 <= 5 C1 : 4X1 + 8X2 <= 48 1 point each 1 point 1 point 1 point 5 points total MAX 24 X
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 + 12 X 2 Subject to: C1: 4 X 1 + 8 X 2 ≤ 48 C2: X 1 ≤ 5 C3: X 2 ≥ 2 C4: X 1 ≥ C5: X 2 ≥ Graphically solve the LP at right in the space provided below. What is the OPTIMAL SOLUTION? ( 5 , 3.5 ) What is the OPTIMAL OBJECTIVE FUNCTION VALUE? ________ 162 ___________ How many corner (extreme) points are there? ________ 4 ___________ What is the slope of the IsoProfit line? _________-2 __________ SOLUTION...
View Full Document

## This note was uploaded on 01/30/2012 for the course MGT 2251 taught by Professor Chang during the Fall '08 term at Georgia Tech.

Ask a homework question - tutors are online