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# homework3 - part is connected across an AC voltage source...

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Physics 334, Winter Quarter 2012 Electric Circuits Laboratory I Homework Assignment 3 Due Tuesday January 31 Note: Sloppy work will not be graded and will receive zero points. 1. A R-C high-pass filter contains a 1 μ F capacitor and a 1k resistor. Suppose a single “square” voltage pulse of 5 V for 1 ms duration is applied to the input. Carefully and neatly sketch the resulting output, including numeric values, of output voltage versus time. 2. A two-terminal “black box” is known to contain an inductor L, a capacitor C, and a resistor R. On connecting a 1.5 V battery, 1.5 mA flows. When an AC voltage of 1V RMS at 60 Hz is connected, 10 mA RMS flows. As the frequency increases at a fixed 1 V RMS, the current reaches a maximum of over 100 A at 1 kHz. Carefully and neatly sketch the circuit in the black box and find values for L, C and R. 3. A load impedance 1000(1 + i) Ω (and note it contains an imaginary
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Unformatted text preview: part) is connected across an AC voltage source of amplitude 10 V and frequency 60 Hz. What ʼ s the power dissipated over one cycle within the load? Comment: There are several ways to attack this problem. For definiteness, my solution started by choosing a specific phase of the voltage so it ʼ s a maximum at t=0. Then I wrote everything in complex form. For those not familiar with complex analysis: To find power, I used the identity that the time-average is ½ the real part of the product of a complex current amplitude times the complex conjugate of the voltage amplitude. See the discussion in the textbook pp. 33-34 (especially the lower left column on p 34: notice the text speaks of “complex RMS amplitudes”) while my factor of ½ comes from using the full complex amplitudes. You can also of course find the time average by directly averaging over a complete cycle....
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