q4_2 - 1200 seconds = 144,000 J. The battery then loses 10...

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Chapter 4 Question 2 Answer: (2) +134 kJ P=VI = 12 V * 10 A = 120 W. The total energy given to the battery is therefore power * time = 120 W *
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Unformatted text preview: 1200 seconds = 144,000 J. The battery then loses 10 kJ so the net increase in internal energy is +134 kJ. Class Response:...
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q4_2 - 1200 seconds = 144,000 J. The battery then loses 10...

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