q7_9 - pressure = 0). Therefore, ∆ u=0. So for an ideal...

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Chapter 7 Question 9 Answer: (2) T 1 = T 2 From the First Law, u = q - w. q=0 since the container is thermally-insulated. w=0 since the container is rigid (or if you draw your system around the gas, because the external
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Unformatted text preview: pressure = 0). Therefore, ∆ u=0. So for an ideal gas then, the temperature is constant since du=cvdT. Class Response (2003): Class Response (2002):...
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This note was uploaded on 01/28/2012 for the course AERO 16.01 taught by Professor Markdrela during the Fall '05 term at MIT.

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q7_9 - pressure = 0). Therefore, ∆ u=0. So for an ideal...

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