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s06_cgs - t and u t are as plotted below Plot g t − τ u...

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Graphical Interpretation of Convolution I The convolution integral is g ( t ) u ( t ) = g ( t τ ) u ( τ ) −∞ Plot g ( t τ ) as a function of τ , for g ( t ) and t as shown. g(t) t g(t- τ )= ? τ t
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Graphical Interpretation of Convolution I Plot g ( t τ ) as a function of τ , for g ( t ) and t as shown. g(t) t My confidence that I have the correct answer is: 1. 100% 2. 80% 3. 60% 4. 40% 5. 20% 6. 0%
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Graphical Interpretation of Convolution I The plot of g ( t τ ) is given by g(t- τ ) τ t My answer 1. Was completely correct 2. Was mostly correct, with one or two minor errors 3. Had many errors 4. Was completely incorrect
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Graphical Interpretation of Convolution II The signals g (
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Unformatted text preview: t ) and u ( t ) are as plotted below. Plot g ( t − τ ) u ( τ ) as a function of τ . g(t) t u(t) t g(t-τ )u( τ )= ? τ t Graphical Interpretation of Convolution II Plot g ( t − τ ) u ( τ ) as a function of τ , for g ( t ) and u ( t ) as shown. g(t) t u(t) t My confidence that I have the correct answer is: 1. 100% 2. 80% 3. 60% 4. 40% 5. 20% 6. 0% Graphical Interpretation of Convolution II The plot of g ( t − τ ) is given by g(t-τ )u( τ ) τ t My answer 1. Was completely correct 2. Was mostly correct, with one or two minor errors 3. Had many errors 4. Was completely incorrect...
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