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Unformatted text preview: but the accelerating bus then catches up to her. At this later time the bus's velocity is ( 29 ( 29 . s m 38 . 8 s 3 . 49 s m 170 . 2 = e) No; , 2 2 ax v < and the roots of the quadratic are imaginary. When the student runs at , s m 5 . 3 , the two lines do not intersect: f) For the student to catch the bus, . 2 2 ax v and so the minimum speed is ( 29 ( 29 s. m 688 . 3 s m 40 s m 170 . 2 2 = She would be running for a time s, 7 . 21 2 m/s 0.170 s m 69 . 3 = and cover a distance ( 29 ( 29 m. . 80 s 7 . 21 s m 688 . 3 = However, when the student runs at s, m 688 . 3 the lines intersect at one point ( x = 80 m)....
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 Velocity, later time

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