Lecture 23 - Recap of last lecture w1/a 85% of the power P...

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Recap of last lecture 85% of the power w α 1/a P will be a dark band if ½asin θ = ½ λ Or sin θ = m λ /a m =±1, ±2, … For small θ sin θ ~ θ ~ tan θ y = xm λ /a with m =±1, ±2, …
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Intensity in a single-slit pattern E p = E 0 sin( β /2)/( β /2) 2 0 β/2 /2 sin I I = β β = (2 π / λ )*[path difference] = ( 2 π / λ )asin θ
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Intensity maxima in a single-slit pattern 2 0 β/2 /2 sin I I = β β 0 Lt = I 0 sin θ = m λ /a m =±1, ±2, … Maxima at β ± (2m+1) π ( m=0,1,2…) I m 2 2 0 π 2 1 m I + Minima at β /2 = m π , m =±1, ±2, … Or 2 π asin θ /2 λ = m π I 1 = 0.0472I 0 I 2 = 0.0165I 0 I 3 = 0.0083I 0
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Width of Interference Pattern The approximation of sin θ = θ is very good considering the size of the slit and the wavelength of the light. The first minima is at θ 1 = λ/ a Therefore the angular width of the central maxima is 2 λ /a Or the linear width = 2x λ /a (it is inversely proportional to the size of the slit).
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Why is that you can hear me speak when I am facing
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Lecture 23 - Recap of last lecture w1/a 85% of the power P...

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