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Unformatted text preview: Version 058 – Exam4 – Hoffmann – (56745) 1 This printout should have 15 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points The unit for the answer choices is centimeter (cm). A concave mirror has a focal length of 36 cm. What is the position of the resulting image if the image is inverted and 4 times smaller than the object? 1. 40.5 2. 64.1667 3. 48.0 4. 45.0 5. 12.25 6. 24.0 7. 90.0 8. 18.2857 9. 61.2 10. 47.5 Correct answer: 45 cm. Explanation: 1 p + 1 q = 1 f = 2 R m = h ′ h = q p Concave Mirror f > ∞ >p> f f <q < ∞ >m>∞ f >p>∞ <q < ∞ >m> 1 Let : f = 36 cm and n = 4 . Since the image is inverted, n = 1 m . From the mirror equation 1 p + 1 q = 1 f and p q = n , so 1 nq + 1 q = 1 f q = ( n + 1) f n = (4 + 1) (36 cm) 4 = 45 cm . 002 10.0 points A beam of light of wavelength 530 nm travel ing in air is incident on a slab of transparent material. Given: The incident beam makes an angle of 40 . 6 ◦ with the normal, and the refracted beam makes an angle of 24 . 7 ◦ with the nor mal. Find the index of refraction of the material. 1. 1.62899 2. 2.32801 3. 1.90638 4. 1.58386 5. 1.93073 6. 2.1496 7. 1.55737 8. 1.79652 9. 1.69718 10. 2.07826 Correct answer: 1 . 55737. Explanation: Snell’s law of refraction n 1 sin θ 1 = n 2 sin θ 2 with these data gives n 2 = n 1 sin θ 1 sin θ 2 = 1 sin(40 . 6 ◦ ) sin(24 . 7 ◦ ) = 1 . 55737 . 003 10.0 points Two parallel polarizer disks are aligned with the transmission axis of the first oriented at an angle θ 1 clockwise from the vertical, and that of the second at an angle θ 2 clockwise from the vertical, with 0 < θ 1 < θ 2 . A horizontal beam of polarized light with intensity I and the polarization direction pointing vertically passes through both polarizers. The intensity I of the light is 1. I = I cos 2 θ 2 . Version 058 – Exam4 – Hoffmann – (56745) 2 2. I = I cos 2 θ 1 cos 2 ( θ 2 θ 1 ) . correct 3. I = I cos 2 θ 2 . 4. I = I cos 2 θ 1 . 5. I = I cos 2 θ 1 cos 2 θ 2 . 6. I = I cos 2 θ 2 cos 2 θ 1 . 7. I = I cos 2 θ 1 cos 2 θ 2 . 8. I = I cos 2 θ 1 . 9. I = I . 10. None of these. Explanation: When polarized light passes through a polarizer, the transmitted intensity is I = I cos 2 θ , where θ is the angle between the di rection of polarization of the light and the axis of the polarizer. Now we have two successive polarizers, so the resulting intensity will be I = I cos 2 θ 1 cos 2 ( θ 2 θ 1 ) . 004 10.0 points The unit for the answer choices is millimeter (mm). Consider the setup of a single slit experi ment. The wavelength of the incident light is λ = 500 nm . The slit width and the distance between the slit and the screen is specified in the figure....
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This note was uploaded on 01/27/2012 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas.
 Spring '08
 Turner

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