# 101007 - EM 306 — Statics TEST 1 Fall 2008 Kontsos Name...

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Unformatted text preview: EM 306 — Statics TEST 1 Fall 2008 - Kontsos Name: EID: Unique Number : Instructions: This is a closed book, closed notes test. You are allowed to use calculators. The duration of the test is 1 hour. Problem 1 150 points): Two forces are exerted on the crankshaft by the connecting rods as shown in Figure 1. The direction cosines of FA are cost)x = - 0.182, cos0y= 0.818, and cosez= 0.545, and its magnitude is 4 kN. The direction cosines of F1; are cost)" = 0.182, cos0y = 0.818, and cos0z = -0.545, and its magnitude is 2 kN. (i) [10 points] Draw a diagram where you clearly show the points of application of the two forcesand «the-Ewe-ferees: (ii) [30 points] Given the two forces in the ﬁgure, compute a single force R and a moment Mo acting at the origin 0. Draw R and Mo on the diagram you presented in (i). (iii) [10 points] If the system of forces that you computed in (ii) should be represented by a single force acting at some point in space, show how you would compute the coordinates of this point by deriving a system of equations (you are not required to solve it). y F3 80 mm 80 mm x Figure 1 4 A Mfg, [30.2% + 363.181 + 55>.“ EM 306 — Statics TEST 1 Fall 2008 - Kontsos Problem 2 150 points ): ,, The 8-ft bar in Figure 2 lies on the x-y plane and is in equilibrium. It is supported by a ball an socket support at point A, the cable BD, and a roller support at C. The collar at B is ﬁxed to the bar at its midpoint. The force F = - 50 k (lb). (i) [20 points] Draw a free body diagram where you clearly show all the forces and reactions on the bar. (ii) [30 points] Determine the tension in cable BD and the reactions at A and C. Figure 2 “EST 1 (Bloaw L (“Q VA ‘33 x \‘WW“ “I l 3 mm 6% )ﬁ 3?? .9 a w} (u) a: an}; “3" / klaere E‘s Wu Cmﬁféw 003% "j" + 00.39% 12;") .4: a ‘f (A: 392%.». oeacsjw Mg”? :3» .49 vb FR: ~0 7626734, 3247341139“? in LN M F5: lFﬂ Cm; £3+m573 1» m8z§\ :1 a; {1%9'13‘1' \$023 x (*0 ﬁgZ‘wB’l’o’f’sz 2‘ '55 ’“ * {m-s- 80:2?) x (0.§é~1’%\$-63é§' 1mg: “5:” _. v w} - —-_) m “‘3 :3) no: Aeoaaqa‘z 2 .— 3.50 2333 \$0 0x233 8o 5.22:2 a. . 1' \$604£3>é§3 + 56m gmj _. 9,9. Qﬁgqj -r 83 ,gdﬁﬁa? :2. '0‘} + hr? =" “0" C \$30-59» ~ mLin + {—3.38 -2Q.n+ 3522 .«a 4—58.2wb i» {32:23 52w mg 2%} 72 m3? aw} ‘ I .359 Mg 4» xaaaé? » mmj «2. Am am '2? mm ~> - - 6r Mo: ~0 13\$ 3~0.0H4”)+ Lle ‘5 Wm (Sh) 33862 [email protected] a} U0 WW «3} we Med 49 4ws£§r 7’3 4a at wm+ C(‘ﬁﬁéy 4&9? w w m; ‘ ﬁg“ .3 K5 2 M in.» v .w) ...;3 ~—-; w.) “a Mxﬁwi} m {XLA—x 3+§z§2¢ (maﬁéq L+L¥RQ§3+L§Q as. .._ MB ~43“ w): mm) a?» £49935? g? -4,.0Q§'j’ +5 5%??? aaawmg; 3:? "Haws; .. qméa L. gun: 2; wk} C may “a MEN? «r c— MW - Mmﬂ'jh Ci§%3‘§+® M); w \ea—‘lrl 3391?“? 908%: :- w O.J.5.L, 43% g~oaﬁ% :2 - awn; me 4m 5mg}: .1411 v 3 etiuoém‘aw mﬂh '5) Uv; 5am: (YA (Envst ma 4%ng Kw} we bmﬁ ” (ng‘agiﬁ‘ WE ( x§:¥9 ,29\ -_—_ Cq’ o 33") 3 mm; aimga .g. ﬁg, gunﬁght 4' (ﬁﬁgﬁ: amer, a") "' .— 0 am} xg- 4 Mﬁa “M0322 .3: xﬁw‘ﬁsﬁcgg ,2: («4.533353% (5303,55?) yea“ “sway 2:» kg” “Mime “'3 m (igkﬂ (Vn*¥e3”’*€%w%3§l WW3 vm‘j’vz 2’ w» 5539 ’ {2 “ ‘1 "1, M ~ (my *{V§W&§%@{QSQ~ Mag}- 01% \$3» % I 43“ “534' 5.. 9 "‘ 3?? E’ “V ”” w .p Y + g: mg ° V A1?" A35" + ’25," 7 ‘9 .4 ‘ :(r _, A ,, \w? aq‘gxg -«>__ .9 wkevc rm Re, 80 “(32> yksf 05% la a, my rim ’3 z. 3.5;} —-7 0 W W “"9 3"? ‘3 VAC: (:1 with 3+ (YJQSE \${a¢% g2 mg} 33\$ ¥€Méezr~ 3:3 .3; :5 an ab {3:08-54 53§x(01l§.7fw0 aqa‘i’j’+o ma? + (axogyw 453wa 2a 12-50%”) + («mg-:3” gﬁﬂx (‘33 :5 .7 \$3.. .— Qamw‘? — 261%ij o (mm am??? “‘33 4573 + 485.43 «r 49466771? «eff/dig? ~2 cm . Ame, +5.L§QTm‘-€S m3) #ﬁW a“; it mac? 2 4293.5; % (4.21 {b :5?sz =X> Aw Gum m at:- szw-‘ﬁﬁw W») jﬂafo a}; AVVOﬁ‘iGTa-cwa my AV \$20.25 (ea) Egaa may A31: enqu'Twsom my, Aaseb (e; 3 Q-‘J J “£2? ,» 2.056 323’); a udﬁi‘f +¥macy°7£fxa ...
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101007 - EM 306 — Statics TEST 1 Fall 2008 Kontsos Name...

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