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Unformatted text preview: ***want a positive ^E so that ^G is negative from equation Overall reaction: FAD + NADH FADH2 + NAD + B. If all at 1 M and products at 10 M FAD: ^E° + (.026/2) ln (10/1) = -.189 NADH: ^E° + (.026/2) ln (1/10) =0.035 Total: -.153 6. Enzyme- hexokinase Glu + ATP Glu-6-phos + ADP ^G= -4000 cal/mol Enzyme- phoshpfructokinase Fruc-6-Phos + ATP Fruc-1,6-bisPhos + ADP ^G= -4000 about A. Mg2+ B. Irreversible basically (need special enzymes) Glucokinase is backward for first regulation points b/c large ^G (all others about 0 so they go back and forth but this one depends on what enzyme is present so it’s a branch point) Second one (fructose) is rate limiting step 7. It inactivates cysteine b/c its sulfur (the catalytic residue) it shuts it all down the product that uses the cysteine is accumulating the step right before glyceraldehyde-3-phosphate dehydrogenase...
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- Spring '09
- Adenosine triphosphate, 1 m, 10 m, glu-6-phos + adp, 1.986 cal, 84.7 kJ