chem233_postlab6 - SN1: Preparation of...

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S N 1: Preparation of 2-Chloro-2-methylbutane 1. Some reasons for only obtaining a 39% yield could include draining the separatory funnel excessively, so that some of the organic layer was lost into the aqueous one at each separation. This would have produced fewer product than theoretically predicted. This is a physical reason, but there could also be a chemical one, as perhaps not all of the t-amyl alcohol reacted and thus did not convert to t-amyl chloride. 2. An IR spectrum would help to show whether or not the product was pure, as a peak for an alcohol would appear if the t-amyl chloride product was not completely converted into and there was still residual starting reactant t-amyl alcohol. Based on the information given to us, then the IR spectrum would not provide data on the reaction mechanism, but if there is a peak for carbocations, which am I unaware of, then the IR spectrum would. If an alkene was formed
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This note was uploaded on 01/29/2012 for the course CHEM 233 taught by Professor Staff during the Spring '08 term at University of Illinois, Urbana Champaign.

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