F12_EMS_160_HW2

F12_EMS_160_HW2 - again tripled. d. The gas is finally...

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HW 2. Due: 10/07/11 NO CREDIT WILL BE GIVEN IF WORK IS NOT SHOWN!! Problems (all from the textbook) 2.8 Two moles of an ideal gas, in an initial state P = 10 atm, V = 5 liters, are taken reversibly in a clockwise direction around a circular path given by (V – 10) 2 + (P – 10) 2 = 25. Calculate the amount of work done by the gas as a result of the process, and calculate the maximum and minimum temperatures attained by the gas during the cycle. 3.1 The initial state of one mole of a monoatomic ideal gas is P = 10 atm and T = 300 K. Calculate the change in the entropy of the gas for (a) an isothermal decrease in the pressure to 5 atm, (b) a reversible adiabatic expansion to a pressure of 5 atm, (c) a constant-volume decrease in the pressure to 5 atm. 3.2 One mole of a monoatomic ideal gas is subjected to the following sequence of steps: a. Starting at 300 K and 10 atm, the gas expands freely into a vacuum to triple its volume b. The gas is next heated reversibly to 400 K at constant volume. c. The gas is reversibly expanded at constant temperature until its volume is
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Unformatted text preview: again tripled. d. The gas is finally reversibly cooled to 300 K at constant pressure. 3.4 Calculate the change in the enthalpy and the change in entropy when 1 mole of SiC is heated from 25 C to 1000 C. The constant pressure molar heat capacity of SiC varies with temperature as c p = 50.79 + 1.97 * 10-3 T 4.92 * 10 6 T-2 + 8.20 * 10 8 T-3 J/mole-K 3.5 One mole of copper at a uniform temperature of 0 C is placed in thermal contact with a second mole of copper which, initially, is at a uniform temperature of 100 C. Calculate the temperature of the 2 mole system, which is contained in a adiabatic enclosure, when thermal equilibrium is attained. Why is the common uniform temperature not exactly 50 C? How much heat is transferred, and how much entropy is produced by the transfer? The constant pressure molar heat capacity of solid copper varies with temperature as c p = 22.64 + 6.28 * 10-3 T J/mol-K...
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F12_EMS_160_HW2 - again tripled. d. The gas is finally...

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