Solution_F12_EMS_160_HW5

Solution_F12_EMS_160_HW5 - #hifllu 8.2 H “70135 Of a”...

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Unformatted text preview: #hifllu 8.2 H “70135 Of a” ideal gas A Emd (1 - n) moles of an idea} gas B, each at 1 atm pressure, are mixgd 3‘ [0‘31 consmm PTCSSUTC. What ratio of A to B in the mixture maximizes the energy of the gas mixture by ‘AAGM? Mix 49 ma/(ra/ r! M [/-— 71) one/t; 4f 3 afcanI/zmz‘ ? 5' /WI A614”: _;_ flT[/nxév% 19 {l—“kfl-fioé— “)2 11/? 4, R7 fllfi :2. d WM’I’V’d; ‘ Max/haw #65641? Mad/f W54” 4’9; "r" “’3 ‘1' A; It ,fl/ltfaf/B 7%! fMJ't/l’t 7V1”; / M‘m 7’2? 7M5" /)~Wf&f 7%: Free 92.64/77 by- - Lg? "Mm: :._m d which is also at 2500 K. solution of A1203 and Cr203 in which cho, = 0.2 an GIT!) M Cf/l) All: Aflm :- crgz) A W41. f'I/wfrlm) M av A 1 Mum = #74on .7 “Mil "' 0 .fl/7_._P‘A”Y:/ : - iii/fl .5. a; =' mg -' 45.25 H33! ;- 57.1; a/K } x '- Army 9.2 When one mole of argon gas is bubbled through a large volume of an Fe-Mn melt of X Mn = 0.5 at 1863 K evaporation of Mn into the A: causes the mass of the melt to decrease by 1.50 g. The gas leaves the melt at a pressure of 1 atm. Calculate the activity coefficient of Mn in the liquid alloy. W7! law/via! Vav/arfr’era/{t If” fl'fd/é/ Wk 4'; 4/13 2" A} $17 (-2422 .. m A w: + 37. a) :- diff! My lib" 777; numéérdf Ibo/#I/ WA far»on 4‘ if? .-- (7.4727? [9‘14 77-4 fa/flé/f/‘(ffd/t 0f fin I; 1%,! far Mfr/If! 3' 477/11, a M73 0%, +4”, : ' .._.._. .4.- d.02;! '7' /. 027i - fly" I' :- fl I " ax”): -t;2- ' -'—' 0:537 f,”,, I; ‘ fl'i ' M file 5 9 Q1 pig). / 2‘ f” xiv/7‘1” N i. 9.4 Calculate the heat required to form a liquid solution at 1356 K starting with 1 mole of Cu and 1 mole of Ag at 298 K. At 1356 K the molar. heat of mixing [of liquid Cu and liquid Ag is given by AH“ — ZOSQOXCUXAg. HM‘L‘ /AM/; if dofldm Zfir’k Jr 35!)? me/Z 17' [if AH: f‘fxtfn"? as Ail/711:6? '3 a. 2. x {1.2444, (/355- 17'!) $23-$51" (/34? - 39’!) 4' H7747 .7" :- 42420 .7. f / k a A 1%». 27 f7 Hf! Has— 72: f j _ 0" fly? A/r -.- f 9,4565,” + A/Ifiwj + f ‘fi/szcM?’ 15; MM: .; 2' ’ =' 21.3 (Mu-2ft) 1‘ fig/é. 0m ~22?) 5'___/_ ____/_ - MN“! ,2“ W) + M174 +3d.fflii/- m?!) .7 4/2614 .7. 71» ‘1 M/z/ a/ qu/kp/A/ flfw'a’ fa brim. , AH : 2[~2M7ow,5 ) r ~ Mm WM 23-54? fdfw'r-{manf :- 47424 + 102.1; ~ #306 .= 73330 .77 9.8 Tin obeys Henry’s law in dilute liquid solutions of Sn and Cd and the Henrian activity coefficient of Sn, T’s“, varies with temperature as mm“ = 434m + 1.58 Calculate the change in temperature when 1 mole of liquid Sn and 99 moles of liquid Cd are mixed in an adiabatic enclosure. The molar constant pressure heat capacity of the alloy formed is 29.5 UK A 4-: : 49,47 : 29,;fl7 ‘ IW/zk 7 =' {7477‘ , 2,37 ke/V/hr 27.; I I ...
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Solution_F12_EMS_160_HW5 - #hifllu 8.2 H “70135 Of a”...

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