Solution_F12_EMS_160_HW7

# Solution_F12_EMS_160_HW7 - run-=— 9.4 Calculate the heat...

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Unformatted text preview: run-=— 9.4 Calculate the heat rammed to form a liquid solution at 1356 K starting with 1 mole of Cu and 1 mole of Ag at 298 K. At 1356 K the molar heat of mixing _of liquid Cu and liquid Ag is given by AH” — 205901: C“X Ag. M = f‘bam‘?‘ + Maw 7-” ' a. 1. f M 54. (/35; 197% 5 5; " (Aw - 2?!) +/177o 3' 17/ -7 s- " 21.3 (/2344?!) 1’ W {/27415773) 2 5' I / - mm 72—3; W) 4- Mia +30.ff/ii/-/2?¥) :- 4/254 3' .m. 1 rho/u a/ (ﬂu/\$54M!” ifm ‘ AH : ¢[~2ﬂii’oxo,5) r . 79754 had? l’de;f(rﬂt/v2‘ .- 4144“ +4024; ~ ll!» .: 73310 ~7". 'a’ fplwﬁdm " “354’? 10.1 Can and Mng are mutually insoluble in the Solid state and form a simple binary eutectic system. Calculate the composition and temperature of the eutectic melt assuming that the liquid solutions are Raoulﬁan. The actual eutectic occurs at X (3an = (145 and T = 1243 K. In In H I x ’5‘ X446 ‘ '- er 7%! (3er //'7u/¢/ur //Mz i A53, = 31204 #5157 :— - 5131M 715025 Fr #14 M55 //7u/dur M; ' 46;, : 55m; ~ szxir : —— 1.317% 72%ﬂ i Ska/fanzdas’ 54/01)»; gill/4 79?; fam/ «If [Me/72%;?” if 7A5 [yd/dc“ ///7i/ ‘6; l 7": /5/7 K W t: 9/5? We aim My}; 1': 7': 1243A: W :7 0,79— '3 E t W Gold and silicon are mutually insoluble in the solid state and form a eutectic system with at eutectic temperature of 636 K and a eutectic composition of X 5i = 0.186. Calculate the Gibbs free energy of the eutectic melt relative to (a) unmixed liquid Au and liquid Si, and (b) unmixed solid Au and solid Si. ﬂz‘ «(ﬂ/V £6,244 5' mm l3J/ﬂﬁfs7/ 2' ((//~7 33/ M A5425 : fazw[/J3'/~ (if? __ 5”“ J, A”)? 1/ _ 30943 GEN!) ’ ﬂ 2 ~ (#5034745 ,u df/é‘)‘ (5/2]? = - ///f‘£7 J- }; AF” r a 0 G§i(s) X53=O.186 Si 08‘- E 10.3 A1203, which melts at 2324 K, and CrzOg, which melts at 2538 K form complete ranges E of solid and liquid solutions. Assuming that AS {1.43203 2 AS; A1203, and that the solid and Q i liquid solutions in the system A1203-Cr203 behave ideally, calculate 1. The temperature at which equilibrium melting begins when an alloy of X A120, = 0.5 is heated. 2. The composition of the melt which ﬁrst forms, 3. The temperature at which equilibrium melting is complete, and 4. The composition of last-formed solid. rag/"MW! 2.7, any it!” .———-—"_ -’ ___.—.- , F7 7' A6“ _ 3255’.” r ’1,” — 5:1: 1. 1‘7 7' .1 /) ’%‘f’//R“/7l“/MMI 7, ﬁt 25.5-I} ‘ _ /-'&# "£21.57 . 1 M- x/ 7 +143) 1 M f- #7727 + ,1 my - 17 [1:]! +5.50) 1 nil-id. Lav/#1 127/“th 7 t 24/] K 1‘ z) 77:: car/W/ML-j //7c//4’uvf cave/(2%). ,2 K I ; Xi“; 557,4”) :- ai/Vy/ {'17—’21 +2919] md 0.5 I. ﬁt,— M. i calf/W 7A: ifw'a’z‘r fam/a/zzﬁw m‘ 32/; a; r 0.; 1221125» (i4 - ,- —/4//9‘ 5 - / Jay/7.5.4114) X _/Zf2f "W " £732 .. 7 / «0.5.635 // 7 +£fﬂ) '47/ 1:”? +iﬂ/i) 7' nil—[4%- 5W” 7 .-.- 24,14 K k 64// 055.14] cphﬂ/{j/"IA /} 51M [ft/x'dgr .- / .- 1,, —/4//;' 25 J +5.67?) ’3" {-4125 £57; _ -K/xr ‘ f 2444 7‘ J 47/57; +£f/f/E -' (7.3; (97 ...
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## This note was uploaded on 01/28/2012 for the course EMS 160 taught by Professor Kim during the Fall '11 term at UC Davis.

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Solution_F12_EMS_160_HW7 - run-=— 9.4 Calculate the heat...

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