EE 330 Exam 2 Fall 2011(1)

EE 330 Exam 2 Fall - EE 330 Exam 2 Fall 2011 Name Instructions This is a 50-minute exam Students may bring 2 page of notes(front and back to this

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Page 1 of 11 EE 330 Name_ _ _ _ _ _ _ _ _ _ _ _ _ _ Exam 2 Fall 2011 Instructions: This is a 50-minute exam. Students may bring 2 page of notes (front and back) to this exam. There are 7 questions and 5 problems. The points allocated to each question are as indicated. The problems are all equally weighted and worth 16 points each if solved correctly. Please solve problems in the space provided on this exam and attach extra sheets only if you run out of space in solving a specific problem. If references semiconductor processes are needed beyond what is given in a specific problem or question, assume a CMOS process is available with the following key process parameters; n C OX =100 A/v 2  p C OX = n C OX /3 ,V TNO =0.5V, V TPO = - 0.5V, C OX =2fF/ 2 , = 0, and    If reference to a bipolar process is made, assume this process has key process parameters J S =10 -15 A/ 2 , β=100 and V AF = ∞. The ratio of Boltzmann’s constant to the charge of an electron is k/q= 8.61E-5 V/K. If any other process parameters are needed, use the process parameters associated with the process described on the attachments to this exam. Specify clearly what process parameters you are using in any solution requiring process parameters. Also attached to this exam are two tables that have information about large and small signal models of devices and basic amplifier structures. 1. (2pts) The gate of transistors is “self-aligned” in most (probably in all) CMOS processes. What is the major significance of this self-alignment? 2. (2pts) In a standard bipolar process, MOS transistors are not available. Yet, there is a device that is available in a bipolar process that is also a square-law device with nearly 0 input current. What device is this?
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EE 330 Exam 2 Fall - EE 330 Exam 2 Fall 2011 Name Instructions This is a 50-minute exam Students may bring 2 page of notes(front and back to this

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